(1) Because of the imaging characteristics of the plane mirror: the distance between the object and the image and the mirror is equal, it is known that the eye chart is 2.5m away from the plane mirror and the small red is 0.4m away from the plane mirror.
Therefore, the distance between the image of the eye chart in the plane mirror is 2.5m, and the distance between Xiaohong and the image of the eye chart in the plane mirror should be 5m-0.4m = 4.6m.:
So the answer is: 4.6;
(2) Make the image point P&; of the object point P, connect P&; with Xiaohong&;s eyes, and the intersection point with the mirror is the incident point O, then connect PO and draw an arrow, as shown in the following figure.